featuretools.primitives.NumberOfWordsInQuotes#

class featuretools.primitives.NumberOfWordsInQuotes(quote_type='both')[source]#

确定字符串中引号内单词的数量.

Description:

给定一个字符串列表,确定每个字符串中引号内单词的数量.

此实现处理Unicode字符.

如果字符串缺失,返回`NaN`.

Parameters:

  • quote_type (str, 可选) – 指定要匹配的引号类型.

  • 参数"single"仅匹配单引号 (' ') –

  • 参数"double"匹配双引号 (" ") –

  • 参数"both"匹配任意类型引号内的单词. –

  • 默认为"both". –

Examples

>>> x = ['"python" java prolog "Diffie-Hellman" "4.99"', "Reach me at 'user@email.com'", "'Here's an interesting example!'"]

>>> number_of_words_in_quotes = NumberOfWordsInQuotes()
>>> number_of_words_in_quotes(x).tolist()
[3, 1, 4]
__init__(quote_type='both')[source]#

Methods

__init__([quote_type])

flatten_nested_input_types(input_types)

将嵌套的列模式输入展平成一个列表.

generate_name(base_feature_names)

generate_names(base_feature_names)

get_args_string()

get_arguments()

get_description(input_column_descriptions[, ...])

get_filepath(filename)

get_function()

Attributes

base_of

base_of_exclude

commutative

default_value

Default value this feature returns if no data found.

description_template

input_types

woodwork.ColumnSchema types of inputs

max_stack_depth

name

Name of the primitive

number_output_features

Number of columns in feature matrix associated with this feature

return_type

ColumnSchema type of return

stack_on

stack_on_exclude

stack_on_self

uses_calc_time

uses_full_dataframe