featuretools.primitives.PunctuationCount#
- class featuretools.primitives.PunctuationCount[source]#
确定字符串中的标点符号数量.
- Description:
给定字符串列表,确定每个字符串中标点符号的数量.查找以下任意字符:
!”#$%&’()*+,-./:;<=>?@[]^_`{|}~
如果字符串缺失,返回 NaN.
Examples
>>> x = ['This is a test file.', 'This is second line', 'third line: $1,000'] >>> punctuation_count = PunctuationCount() >>> punctuation_count(x).tolist() [1.0, 0.0, 3.0]
Methods
__init__()flatten_nested_input_types(input_types)将嵌套的列模式输入展平成一个列表.
generate_name(base_feature_names)generate_names(base_feature_names)get_args_string()get_arguments()get_description(input_column_descriptions[, ...])get_filepath(filename)get_function()process_text(text)Attributes
base_ofbase_of_excludecommutativedefault_valueDefault value this feature returns if no data found.
description_templateinput_typeswoodwork.ColumnSchema types of inputs
max_stack_depthnameName of the primitive
number_output_featuresNumber of columns in feature matrix associated with this feature
return_typeColumnSchema type of return
stack_onstack_on_excludestack_on_selfuses_calc_timeuses_full_dataframe