polars.Series.unique_counts#

Series.unique_counts() Series[source]#

返回按出现顺序排列的唯一值的计数。

示例

>>> s = pl.Series("id", ["a", "b", "b", "c", "c", "c"])
>>> s.unique_counts()
shape: (3,)
Series: 'id' [u32]
[
    1
    2
    3
]