pymc.math.stack

pymc.math.stack(tensors, axis=0)

在给定的轴上按顺序堆叠张量（默认是0）。

取一系列的张量或类似张量的常量，并在给定的轴上堆叠它们以形成一个单独的张量。结果在维度 axis 的大小将等于传入的张量数量。

参数:

tensorsSequence[TensorLike]

要堆叠的张量或类张量常量列表。

轴 : intint

新轴的索引。默认值为 0。

示例

>>> a = pytensor.tensor.type.scalar()
>>> b = pytensor.tensor.type.scalar()
>>> c = pytensor.tensor.type.scalar()
>>> x = pytensor.tensor.stack([a, b, c])
>>> x.ndim # x is a vector of length 3.
1
>>> a = pytensor.tensor.type.tensor4()
>>> b = pytensor.tensor.type.tensor4()
>>> c = pytensor.tensor.type.tensor4()
>>> x = pytensor.tensor.stack([a, b, c])
>>> x.ndim # x is a 5d tensor.
5
>>> rval = x.eval(dict((t, np.zeros((2, 2, 2, 2))) for t in [a, b, c]))
>>> rval.shape # 3 tensors are stacked on axis 0
(3, 2, 2, 2, 2)
>>> x = pytensor.tensor.stack([a, b, c], axis=3)
>>> x.ndim
5
>>> rval = x.eval(dict((t, np.zeros((2, 2, 2, 2))) for t in [a, b, c]))
>>> rval.shape # 3 tensors are stacked on axis 3
(2, 2, 2, 3, 2)
>>> x = pytensor.tensor.stack([a, b, c], axis=-2)
>>> x.ndim
5
>>> rval = x.eval(dict((t, np.zeros((2, 2, 2, 2))) for t in [a, b, c]))
>>> rval.shape # 3 tensors are stacked on axis -2
(2, 2, 2, 3, 2)